6x/x^2-25=30/x^2-25-3/x+5

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Solution for 6x/x^2-25=30/x^2-25-3/x+5 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(6*x)/(x^2)-25 = 30/(x^2)-(3/x)-25+5 // - 30/(x^2)-(3/x)-25+5

(6*x)/(x^2)+3/x-(30/(x^2))-25-5+25 = 0

(6*x)/(x^2)+3/x-30*x^-2-25-5+25 = 0

9*x^-1-30*x^-2-5 = 0

t_1 = x^-1

9*t_1^1-30*t_1^2-5 = 0

9*t_1-30*t_1^2-5 = 0

DELTA = 9^2-(-30*(-5)*4)

DELTA = -519

DELTA < 0

x belongs to the empty set

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